[FIXED] 3 condition python while loop regarding checking if two dates are the same

Issue

I'm currently working on this problem of counting how many days between two dates including leap years.
However it keeps skipping the loop from the beginning, even though the two months and days aren't the same?

def daysBetweenDates(year1, month1, day1, year2, month2, day2):
    day_count = 0
    while (year2 != year1) and (month2 != month1) and (day2! = day 1): 
       # print "in loop" // tester
        if (day2 != 0):
            day2 = day2 - 1
            day_count = day_count + 1
        else:
            if(month2 != 0):
                month2 = month2 - 1
                if month2 == (9 or 4 or 6 or 11):
                    day2 = 30
                if month2 == 2:
                    day2 = 28
                if (month2 == 2) and (year2 % 4):
                    day2 = 29
                else:
                    day2 == 31
            else:

                year2 = year2 - 1
                month2 = 12
    #print day_count //tester
    return day_count

# Test routine

def test():
    test_cases = [((2012,1,1,2012,2,28), 58), 
                  ((2012,1,1,2012,3,1), 60),
                  ((2011,6,30,2012,6,30), 366),
                  ((2011,1,1,2012,8,8), 585 ),
                  ((1900,1,1,1999,12,31), 36523)]
    for (args, answer) in test_cases:
        result = daysBetweenDates(*args)
        if result != answer:
            print "Test with data:", args, "failed"
        else:
            print "Test case passed!"

test()

Solution

Here's one way.

>>> from datetime import datetime
>>> diff = datetime(2012, 2, 28)-datetime(2012, 1, 1)
>>> diff.days
58

Answered By - Bill Bell