[FIXED] How to find sibling element of a tag

Issue

I have an html that looks like this:

<h3>
<a href="google.com">hellw</a>
</h3>
<ol>
  <li>
  ....
  </li>
</ol>
<h3>
<a href= "dddd">dddd</a>
</h3>
<ol>
  <li>
    <ol>
  ....
  </li>
</ol>

I want to get ol next to h3. I have tried this but it isnt working

soup = BeautifulSoup(html_string)
print(soup.h3.next_element)

This gives out a inside of h3. How do I get all the ols in a list?

Edit:

I have tried this but it only gives me lis within the first ol tags = soup.h3.nextSibling.find_all()

and not all ols.

I need ols in a list so I could iterate it later.

Solution

You can first grab all h3 tags in a list. Once you have this done, just find all ol tags while iterating through that list. It would look something like this:

html_string = """
   ...
"""

soup = BeautifulSoup(html_string, 'html.parser')

# all h3 tags
h3_tags = soup.find_all('h3')

# all ol tags
ol_tags = [each_h3.find_next('ol') for each_h3 in h3_tags]

This will give you output of:

[<ol>
<li>
  ....
  </li>
</ol>, <ol>
<li>
<ol>
  ....
  </ol></li>
</ol>]

Answered By - Rustam Garayev