Issue
I want to add a link to a method in my class from within the docstring of another method of the same class. I want the link to work in sphinx and preferentially also in Spyder and other Python IDE's.
I tried several options and found only one that works, but it's cumbersome.
Suppose the following structure in mymodule.py
def class MyClass():
def foo(self):
print 'foo'
def bar(self):
"""This method does the same as <link to foo>"""
print 'foo'
I tried the following options for <link to foo>
:
- :func:`foo`
- :func:`self.foo`
- :func:`MyClass.foo`
- :func:`mymodule.MyClass.foo`
The only one that effectively produces a link is :func:`mymodule.MyClass.foo`, but the link is shown as mymodule.MyClass.foo()
and I want a link that is shown as foo()
or foo
.
None of the options above produces a link in Spyder.
Thanks for your help.
Solution
The solution that works for Sphinx is to prefix the reference with ~
.
Per the Sphinx documentation on Cross-referencing Syntax,
If you prefix the content with ~, the link text will only be the last component of the target. For example, :py:meth:
~Queue.Queue.get
will refer to Queue.Queue.get but only display get as the link text.
So the answer is:
class MyClass():
def foo(self):
print 'foo'
def bar(self):
"""This method does the same as :func:`~mymodule.MyClass.foo`"""
print 'foo'
This results in an html looking like this : This method does the same as foo()
, and foo()
is a link.
However, note that this may not display in Spyder as a link.
Answered By - saroele
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