[FIXED] Python: min(None, x)

Issue

I would like to perform the following:

a=max(a,3)
b=min(b,3)

However sometimes a and b may be None.
I was happy to discover that in the case of max it works out nicely, giving my required result 3, however if b is None, b remains None...

Anyone can think of an elegant little trick to make min return the number in case one of the arguments in None?

Solution

Why don't you just create a generator without None values? It's simplier and cleaner.

>>> l=[None ,3]
>>> min(i for i in l if i is not None)
3

Answered By - utdemir