Issue
I was using asyncio for a project, and encountered this strange behavior.
import asyncio
def schedule_something():
global f
tsk = asyncio.async(do_something())
f = tsk #If this line is commented out, exceptions can be heard.
@asyncio.coroutine
def do_something():
raise Exception()
loop = asyncio.get_event_loop()
loop.call_soon(schedule_something)
loop.run_forever()
loop.close()
For some reason, storing the resulting task when you call asyncio.async()
stops exceptions from doing anything.
Could someone shed some light on this situation? I need to have a way to catch exceptions in my current project.
Solution
This is because the exception only gets raised if the Task
is destroyed without ever having its result retrieved. When you assigned the Task
to a global variable, it will always have an active reference, and therefore never be destroyed. There's a docstring in asyncio/futures.py that goes into detail on this:
class _TracebackLogger:
"""Helper to log a traceback upon destruction if not cleared.
This solves a nasty problem with Futures and Tasks that have an
exception set: if nobody asks for the exception, the exception is
never logged. This violates the Zen of Python: 'Errors should
never pass silently. Unless explicitly silenced.'
However, we don't want to log the exception as soon as
set_exception() is called: if the calling code is written
properly, it will get the exception and handle it properly. But
we *do* want to log it if result() or exception() was never called
-- otherwise developers waste a lot of time wondering why their
buggy code fails silently.
An earlier attempt added a __del__() method to the Future class
itself, but this backfired because the presence of __del__()
prevents garbage collection from breaking cycles. A way out of
this catch-22 is to avoid having a __del__() method on the Future
class itself, but instead to have a reference to a helper object
with a __del__() method that logs the traceback, where we ensure
that the helper object doesn't participate in cycles, and only the
Future has a reference to it.
The helper object is added when set_exception() is called. When
the Future is collected, and the helper is present, the helper
object is also collected, and its __del__() method will log the
traceback. When the Future's result() or exception() method is
called (and a helper object is present), it removes the the helper
object, after calling its clear() method to prevent it from
logging.
If you want to see/handle the exception, just use add_done_callback
to handle the result of the task, and do whatever is necessary when you get an exception:
import asyncio
def handle_result(fut):
if fut.exception():
fut.result() # This will raise the exception.
def schedule_something():
global f
tsk = asyncio.async(do_something())
tsk.add_done_callback(handle_result)
f = tsk
@asyncio.coroutine
def do_something():
raise Exception()
loop = asyncio.get_event_loop()
loop.call_soon(schedule_something)
loop.run_forever()
loop.close()
Answered By - dano
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