[FIXED] open() function python default directory

Issue

I'm new and I have no idea where the default directory for the open() function is.

For example open('whereisthisdirectory.txt','r')

Can someone advise me? I've tried googling it (and looking on stackoverflow) and even putting a random txt file in so many folders but I still can't figure it out. Since I'm beginning, I want to learn immediately rather than type "c:/directory/whatevevr.txt" every time I want to open a file. Thanks!

Ps my python directory has been installed to C:\Python32 and I'm using 3.2

Solution

os.getcwd()

Shows the current working directory, that's what open uses for for relative paths. You can change it with os.chdir.

Answered By - dav1d