[FIXED] PYTHON - finding the maximum of every 10 integers in an array

Issue

I have a large array of integers, and I need to print the maximum of every 10 integers and its corresponding index in the array as a pair.

ex. (max_value, index of max_value in array)

I can successfully find the maximum value and the corresponding index within the first 10 integers, however I am having trouble looping through the entire array.

I have tried using:

a = some array of integers

split = [a[i:i+10] for i in xrange(0, len(a), 10)] 

for i in split:
    j = max(i) 
    k = i.index(max(i))
    print (j,k)

The issue with this method is that it splits my array into chunks of 10 so the max_values are correct, but the indexes are inaccurate (all of the indexes are between 0-10.) I need to find a way of doing this that doesn't split my array into chunks so that the original indices are retained. I'm sure there is an easier way of looping through to find max values but I can't seem to figure it out.

Solution

So with debugging with an example array, we find that split returns a 2d list like this one:

[[1, 2, 3, 4, 5, 6, 7, 8, 9, 10], [11, 12, 13, 14, 15, 16, 17, 18, 19, 20]]

And every time the for loop runs, it does through one of those lists in order. First it goes through the first inner list then the second one etc. So every time the for loop jumps into the next list, we simply add 10. Since the list can have over 2 lists in them, we store the number we need to add in a variable and add 10 to it every loop:

a = [1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15, 16, 17, 18, 19, 20]
split = [a[i:i+10] for i in xrange(0, len(a), 10)] 
counter = 0

for i in split:
    j = max(i) 
    k = i.index(max(i))
    print (j,k+counter)
    counter += 10

You can test it here

Answered By - Anthony Pham