Issue
I have 10s of text files in my local directory named something like test1, test2, test3, and so on. I would like to read all these files, search few strings in the files, replace them by other strings and finally save back into my directory in such a way that something like newtest1, newtest2, newtest3, and so on.
For instance, if there was a single file, I would have done following:
#Read the file
with open('H:\\Yugeen\\TestFiles\\test1.txt', 'r') as file :
filedata = file.read()
#Replace the target string
filedata = filedata.replace('32-83 Days', '32-60 Days')
#write the file out again
with open('H:\\Yugeen\\TestFiles\\newtest1.txt', 'w') as file:
file.write(filedata)
Is there any way that I can achieve this in python?
Solution
If you use Pyhton 3 you can use the scandir
in os library.
Python 3 docs: os.scandir
With that you can get the directory entries.
with os.scandir('H:\\Yugeen\\TestFiles') as it:
Then loop over these entries and your code could look something like this.
Notice I changed the path in your code to the entry object path.
import os
# Get the directory entries
with os.scandir('H:\\Yugeen\\TestFiles') as it:
# Iterate over directory entries
for entry in it:
# If not file continue to next iteration
# This is no need if you are 100% sure there is only files in the directory
if not entry.is_file():
continue
# Read the file
with open(entry.path, 'r') as file:
filedata = file.read()
# Replace the target string
filedata = filedata.replace('32-83 Days', '32-60 Days')
# write the file out again
with open(entry.path, 'w') as file:
file.write(filedata)
If you use Pyhton 2 you can use listdir. (also applicable for python 3)
Python 2 docs: os.listdir
In this case same code structure. But you also need to handle the full path to file since listdir will only return the filename.
Answered By - akane
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