[FIXED] Asyncio.sleep blocking the rest of the function

Issue

Function cant pass to next line because of asyncio.sleep. There is rest of the code but i will share just 3 lines. It explains everything. Console doesnt print 0 to console. If i move print(0) above of asyncio.sleep it prints to console.

async def getHistory(self):
    logging.info(f"Getting history for {self.parite}...")
    await asyncio.sleep(1)
    print(0)

async def get_histories():
    for parite in parite_list:
        asyncio.create_task(parite.getHistory())

asyncio.run(get_histories())

Solution

It looks like you created the tasks but did not execute them. Try this with asyncio.gather:

import asyncio
import logging

async def getHistory(num):
    print(f"Getting history for {num}...")
    await asyncio.sleep(1)
    print(num)

async def get_histories():
    await asyncio.gather(
        asyncio.create_task(getHistory(1)),
        asyncio.create_task(getHistory(2)),
        asyncio.create_task(getHistory(3))
    )

asyncio.run(get_histories())

Result:

% python asdf.py
Getting history for 1...
Getting history for 2...
Getting history for 3...
1
2
3

Answered By - Matthew Trotter