[FIXED] Check if list is sublist of another list and the elements are in the same order

Issue

#sub list test 1
a = [1,1,2]
b = [0, 1,1,1,2,1]

#sub list test 2
c = [4,5]
d = [2,3,4,5,6]

if all(i in a for i in b):
   print("Yes I have all the elements but not sure about their order :( ")

I have tried all() or using counter() from collections module. I can't seem to figure it out how to check their order too.

Solution

This will check all subList of length a and return True if a is found in b

Not sure about order :

def isSublist(a,b):
    #checking all unique elements and their count
    for i in set(a):
        if i not in b or a.count(i) > b.count(i):
             return False
    return True

Sure about order :

def isSublist(a,b):
    for i in range(len(b)-len(a)+1):
        if b[i:i+len(a)] == a:
            return True
    return False

Answered By - THUNDER 07