Issue
I've seen some example code for PySide slots that uses the @QtCore.Slot decorator, and some that does not. Testing it myself, it doesn't seem to make a difference. Is there a reason I should or should not use it? For example, in the following code:
import sys
from PySide import QtCore
# the next line seems to make no difference
@QtCore.Slot()
def a_slot(s):
print s
class SomeClass(QtCore.QObject):
happened = QtCore.Signal(str)
def __init__(self):
QtCore.QObject.__init__(self)
def do_signal(self):
self.happened.emit("Hi.")
sc = SomeClass()
sc.happened.connect(a_slot)
sc.do_signal()
the @QtCore.Slot decorator makes no difference; I can omit it, call @QtCore.Slot(str), or even @QtCore.Slot(int), and it still nicely says, "Hi."
The same seems to be true for PyQt's pyqtSlot.
Solution
This link explains the following about the pyqtSlot
decorator:
Although PyQt4 allows any Python callable to be used as a slot when connecting signals, it is sometimes necessary to explicitly mark a Python method as being a Qt slot and to provide a C++ signature for it. PyQt4 provides the pyqtSlot() function decorator to do this.
and
Connecting a signal to a decorated Python method also has the advantage of reducing the amount of memory used and is slightly faster.
Since the pyqtSlot
decorator can take additional argument such as name
, it allows different Python methods to handle the different signatures of a signal.
If you don't use the slot decorator, the signal connection mechanism has to manually work out all the type conversions to map from the underlying C++ function signatures to the Python functions. When the slot decorators are used, the type mapping can be explicit.
Answered By - Austin Phillips
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