[FIXED] Pop-up saying element not interactable Selenium

Issue

There are two pop-ups: One that asks if you live in California and the second one looks like this:

Here is my code:

The second pop-up doesn't show up every time and when it doesn't the function works. When it does I get an element not interactable error and I don't know why. Here is the inspector for the second pop-up close-btn.

test_data = ['Los Angeles','San Ramon']
base_url = "https://www.hunterdouglas.com/locator"

def pop_up_one(base_url):
    driver.get(base_url)
    try:
        submit_btn = WebDriverWait(driver,5).until(EC.element_to_be_clickable((By.CSS_SELECTOR,"[aria-label='No, I am not a California resident']")))
        submit_btn.click()
        time.sleep(5)
        url = driver.current_url
        submit_btn = WebDriverWait(driver,5).until(EC.presence_of_element_located((By.XPATH, "//*[contains(@class,'icon')]")))
        print(submit_btn.text)
        #submit_btn.click()
    except Exception as t:
        url = driver.current_url
        print(t)
        return url
    else:
        url = driver.current_url
        print("second pop_up clicked")
        return url 

I have tried selecting by the aria-label, class_name, xpath, etc. the way I have it now shows that there is a selenium web element when I print just the element but it doesn't let me click it for some reason. Any direction appreciated. Thanks!

Solution

There are 41 elements on that page matching the //*[contains(@class,'icon')] XPath locator. At least the first element is not visible and not clickable, so when you trying to click this submit_btn element this gives element not interactable error.
In case this element is not always appearing you should use logic clicking element only in case the element appeared.
With the correct, unique locator you code can be something like this:

submit_btn = WebDriverWait(driver,5).until(EC.element_to_be_clickable((By.CSS_SELECTOR,"[aria-label='No, I am not a California resident']")))
submit_btn.click()
time.sleep(5)
url = driver.current_url
submit_btn = driver.find_elements_by_xpath('button[aria-label="Close"]')
if(submit_btn):
    submit_btn[0].click()

Here I'm using find_elements_by_xpath, this returns a list of web elements. In case element was not found it will be an empty list, it is interpreted as Boolean False in Python.
In case the element is found we will click on the first element in the returned list which will obviously the desired element.
UPD
See the correct locator used here.
It can also be in XPath syntax as //button[@aria-label="Close"]

Answered By - Prophet