Issue
import scrapy
from selenium import webdriver
class ProductSpider(scrapy.Spider):
name = "product_spider"
allowed_domains = ['ebay.com']
start_urls = ['http://www.ebay.com/sch/i.html?_odkw=books&_osacat=0&_trksid=p2045573.m570.l1313.TR0.TRC0.Xpython&_nkw=python&_sacat=0&_from=R40']
def __init__(self):
self.driver = webdriver.Firefox()
def parse(self, response):
self.driver.get(response.url)
while True:
next = self.driver.find_element_by_xpath('//td[@class="pagn-next"]/a')
try:
next.click()
# get the data and write it to scrapy items
except:
break
self.driver.close()
selenium with scrapy for dynamic page
This solution works good, but it requests twice for the same url one by scrapy scheduler and another by the selenium web driver.
It'll take twice the time to finish the job, compared to scrapy request without selenium. How to avoid this?
Solution
Here is a trick that can be useful to solve this problem.
create a web service for the selenium run it, locally
from flask import Flask, request, make_response
from flask_restful import Resource, Api
from selenium import webdriver
from selenium.webdriver.chrome.options import Options
app = Flask(__name__)
api = Api(app)
class Selenium(Resource):
_driver = None
@staticmethod
def getDriver():
if not Selenium._driver:
chrome_options = Options()
chrome_options.add_argument("--headless")
Selenium._driver = webdriver.Chrome(chrome_options=chrome_options)
return Selenium._driver
@property
def driver(self):
return Selenium.getDriver()
def get(self):
url = str(request.args['url'])
self.driver.get(url)
return make_response(self.driver.page_source)
api.add_resource(Selenium, '/')
if __name__ == '__main__':
app.run(debug=True)
now http://127.0.0.1:5000/?url=https://stackoverflow.com/users/5939254/yash-pokar will return you the compiled web page using selenium Chrome/Firefox driver.
now how our spider will look like,
import scrapy
import urllib
class ProductSpider(scrapy.Spider):
name = 'products'
allowed_domains = ['ebay.com']
urls = [
'http://www.ebay.com/sch/i.html?_odkw=books&_osacat=0&_trksid=p2045573.m570.l1313.TR0.TRC0.Xpython&_nkw=python&_sacat=0&_from=R40',
]
def start_requests(self):
for url in self.urls:
url = 'http://127.0.0.1:5000/?url={}'.format(urllib.quote(url))
yield scrapy.Request(url)
def parse(self, response):
yield {
'field': response.xpath('//td[@class="pagn-next"]/a'),
}
Answered By - Yash Pokar
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