Issue
When I type small integers with a 0 in front into python, they give weird results. Why is this?
>>> 011
9
>>> 0100
64
>>> 027
23
I'm using Python 2.7.3. I have tested this in Python 3.0, and apparently this is now an error. So it is something version-specific.
They are apparently still integers:
>>> type(027)
<type 'int'>
Solution
These are numbers represented in base 8 (octal numbers). Some examples:
Python 2 (old format)
Note: these forms only work on Python 2.x.
011
is equal to 1⋅8¹ + 1⋅8⁰ = 9,
0100
is equal to 1⋅8² + 0⋅8¹ + 0⋅8⁰ = 64,
027
is equal to 2⋅8¹ + 7⋅8⁰ = 16 + 7 = 23.
Python 3 (new format)
In Python 3, one must use 0o
instead of just 0
to indicate an octal constant, e.g. 0o11
or 0o27
, etc. Python 2.x versions >= 2.6 supports both the new and the old format.
0o11
is equal to 1⋅8¹ + 1⋅8⁰ = 9,
0o100
is equal to 1⋅8² + 0⋅8¹ + 0⋅8⁰ = 64,
0o27
is equal to 2⋅8¹ + 7⋅8⁰ = 16 + 7 = 23.
Answered By - unutbu
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