[FIXED] How to make trapezoid and parallelogram in python using matplotlib

Issue

I have tried the following to produce a regular polygon:

import matplotlib.pyplot as plt
import matplotlib.patches as patches
fig2 = plt.figure()
ax2 = fig2.add_subplot(111, aspect='equal')
ax2.add_patch(
    patches.RegularPolygon(
        (0.5, 0.5),
        3,
        0.2,
        fill=False      # remove background
    )
)

fig2.savefig('reg-polygon.png', dpi=90, bbox_inches='tight')
plt.show()   

While this produces a triangle, I haven't found any way to produce a trapezoid and and a parallelogram.
Are there any commands to do this? Or can I transform the regular polygon into one of the other shapes?

Solution

You would need to use a matplotlib.patches.Polygon and define the corners yourself.

import matplotlib.pyplot as plt
import matplotlib.patches as patches

fig = plt.figure()
ax = fig.add_subplot(111, aspect='equal')

# Parallelogram
x = [0.3,0.6,.7,.4]
y = [0.4,0.4,0.6,0.6]
ax.add_patch(patches.Polygon(xy=list(zip(x,y)), fill=False))

# Trapez
x = [0.3,0.6,.5,.4]
y = [0.7,0.7,0.9,0.9]
ax.add_patch(patches.Polygon(xy=list(zip(x,y)), fill=False))

plt.show()  

For filled patches with size greater than 1 x 1

fig = plt.figure()
ax = fig.add_subplot(111, aspect='equal')
ax.set_xlim(0, 3)
ax.set_ylim(0, 3)

x = [0, 1.16, 2.74, 2, 0]
y = [0, 2.8, 2.8, 0, 0]
ax.add_patch(patches.Polygon(xy=list(zip(x,y)), fill=True))

x = [0.3,0.6,.5,.4]
y = [0.7,0.7,0.9,0.9]
ax.add_patch(patches.Polygon(xy=list(zip(x,y)), fill=True, color='magenta'))

Answered By - ImportanceOfBeingErnest