Issue
In the GroupKFold
source, the random_state
is set to None
def __init__(self, n_splits=3):
super(GroupKFold, self).__init__(n_splits, shuffle=False,
random_state=None)
Hence, when run multiple times (code from here)
import numpy as np
from sklearn.model_selection import GroupKFold
for i in range(0,10):
X = np.array([[1, 2], [3, 4], [5, 6], [7, 8]])
y = np.array([1, 2, 3, 4])
groups = np.array([0, 0, 2, 2])
group_kfold = GroupKFold(n_splits=2)
group_kfold.get_n_splits(X, y, groups)
print(group_kfold)
for train_index, test_index in group_kfold.split(X, y, groups):
print("TRAIN:", train_index, "TEST:", test_index)
X_train, X_test = X[train_index], X[test_index]
y_train, y_test = y[train_index], y[test_index]
print(X_train, X_test, y_train, y_test)
print
print
o/p
GroupKFold(n_splits=2)
('TRAIN:', array([0, 1]), 'TEST:', array([2, 3]))
(array([[1, 2],
[3, 4]]), array([[5, 6],
[7, 8]]), array([1, 2]), array([3, 4]))
('TRAIN:', array([2, 3]), 'TEST:', array([0, 1]))
(array([[5, 6],
[7, 8]]), array([[1, 2],
[3, 4]]), array([3, 4]), array([1, 2]))
GroupKFold(n_splits=2)
('TRAIN:', array([0, 1]), 'TEST:', array([2, 3]))
(array([[1, 2],
[3, 4]]), array([[5, 6],
[7, 8]]), array([1, 2]), array([3, 4]))
('TRAIN:', array([2, 3]), 'TEST:', array([0, 1]))
(array([[5, 6],
[7, 8]]), array([[1, 2],
[3, 4]]), array([3, 4]), array([1, 2]))
etc ...
The splits are identical.
How do I set a random_state
for GroupKFold
in order to get a different (but repoducible) set of splits over a few different trials of cross validation?
Eg, I want
GroupKFold(n_splits=2, random_state=42)
('TRAIN:', array([0, 1]),
'TEST:', array([2, 3]))
('TRAIN:', array([2, 3]),
'TEST:', array([0, 1]))
GroupKFold(n_splits=2, random_state=13)
('TRAIN:', array([0, 2]),
'TEST:', array([1, 3]))
('TRAIN:', array([1, 3]),
'TEST:', array([0, 2]))
So far, it seems a strategy might be to use a sklearn.utils.shuffle
first, as suggested in this post. However, this actually just rearranges the elements of each fold --- it doesn't give us new splits.
from sklearn.utils import shuffle
from sklearn.model_selection import GroupKFold
import numpy as np
import sys
import pdb
random_state = int(sys.argv[1])
X = np.arange(20).reshape((10,2))
y = np.arange(10)
groups = np.array([0,0,0,1,2,3,4,5,6,7])
def cv(X, y, groups, random_state):
X_s, y_s, groups_s = shuffle(X,y, groups, random_state=random_state)
cv_out = GroupKFold(n_splits=2)
cv_out_splits = cv_out.split(X_s, y_s, groups_s)
for train, test in cv_out_splits:
print "---"
print X_s[test]
print y_s[test]
print "test groups", groups_s[test]
print "train groups", groups_s[train]
pdb.set_trace()
print "***"
cv(X, y, groups, random_state)
The output:
>python sshuf.py 32
***
---
[[ 2 3]
[ 4 5]
[ 0 1]
[ 8 9]
[12 13]]
[1 2 0 4 6]
test groups [0 0 0 2 4]
train groups [7 6 1 3 5]
---
[[18 19]
[16 17]
[ 6 7]
[10 11]
[14 15]]
[9 8 3 5 7]
test groups [7 6 1 3 5]
train groups [0 0 0 2 4]
>python sshuf.py 234
***
---
[[12 13]
[ 4 5]
[ 0 1]
[ 2 3]
[ 8 9]]
[6 2 0 1 4]
test groups [4 0 0 0 2]
train groups [7 3 1 5 6]
---
[[18 19]
[10 11]
[ 6 7]
[14 15]
[16 17]]
[9 5 3 7 8]
test groups [7 3 1 5 6]
train groups [4 0 0 0 2]
Solution
KFold
is only randomized ifshuffle=True
. Some datasets should not be shuffled.GroupKFold
is not randomized at all. Hence therandom_state=None
.GroupShuffleSplit
may be closer to what you're looking for.
A comparison of the group-based splitters:
- In
GroupKFold
, the test sets form a complete partition of all the data. LeavePGroupsOut
leaves all possible subsets of P groups out, combinatorially; test sets will overlap for P > 1. Since this meansP ** n_groups
splits altogether, often you want a small P, and most often wantLeaveOneGroupOut
which is basically the same asGroupKFold
withk=1
.GroupShuffleSplit
makes no statement about the relationship between successive test sets; each train/test split is performed independently.
As an aside,
Dmytro Lituiev has proposed an alternative GroupShuffleSplit
algorithm which is better at getting the right number of samples (not merely the right number of groups) in the test set for a specified test_size
.
Answered By - joeln
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