[FIXED] How to remove punctuation marks from a list of strings without using libraries in Python 3.x?

Issue

I need to remove all punctuation marks (without being specific) and '\n' from a list of strings as for example:

l = ['``What ails you, Sister Erin, that your face\n', 'Is, like your mountains, still bedewed with tears?\n', 'As though some ancient sorrow or disgrace,\n']

output:

['What ails you Sister Erin that your face', 'Is like your mountains still bedewed with tears', 'As though some ancient sorrow or disgrace']

I'm trying to do it without using libraries.

Solution

You don't have to use any external libraries for this. The basic str type can deal with this.

See below:

l = ['``What ails you, Sister Erin, that your face\n', 'Is, like your mountains, still bedewed with tears?\n',
     'As though some ancient sorrow or disgrace,\n']

l = ["".join([char for char in line if char.isalnum() or char == " "]) for line in l]
print(l)

You just need to ignore all characters which are not alphanumeric or space

Answered By - Kris