Issue
So this is embarrassing. I've got an application that I threw together in Flask
and for now it is just serving up a single static HTML page with some links to CSS and JS. And I can't find where in the documentation Flask
describes returning static files. Yes, I could use render_template
but I know the data is not templatized. I'd have thought send_file
or url_for
was the right thing, but I could not get those to work. In the meantime, I am opening the files, reading content, and rigging up a Response
with appropriate mimetype:
import os.path
from flask import Flask, Response
app = Flask(__name__)
app.config.from_object(__name__)
def root_dir(): # pragma: no cover
return os.path.abspath(os.path.dirname(__file__))
def get_file(filename): # pragma: no cover
try:
src = os.path.join(root_dir(), filename)
# Figure out how flask returns static files
# Tried:
# - render_template
# - send_file
# This should not be so non-obvious
return open(src).read()
except IOError as exc:
return str(exc)
@app.route('/', methods=['GET'])
def metrics(): # pragma: no cover
content = get_file('jenkins_analytics.html')
return Response(content, mimetype="text/html")
@app.route('/', defaults={'path': ''})
@app.route('/<path:path>')
def get_resource(path): # pragma: no cover
mimetypes = {
".css": "text/css",
".html": "text/html",
".js": "application/javascript",
}
complete_path = os.path.join(root_dir(), path)
ext = os.path.splitext(path)[1]
mimetype = mimetypes.get(ext, "text/html")
content = get_file(complete_path)
return Response(content, mimetype=mimetype)
if __name__ == '__main__': # pragma: no cover
app.run(port=80)
Someone want to give a code sample or url for this? I know this is going to be dead simple.
Solution
The preferred method is to use NGINX or another web server to serve static files; they'll be able to do it more efficiently than Flask.
However, you can use send_from_directory
to send files from a directory, which can be pretty convenient in some situations:
from flask import Flask, request, send_from_directory
# set the project root directory as the static folder, you can set others.
app = Flask(__name__, static_url_path='')
@app.route('/js/<path:path>')
def send_js(path):
return send_from_directory('js', path)
if __name__ == "__main__":
app.run()
Alternatively, you could use app.send_file
or app.send_static_file
, but this is highly discouraged as it can lead to security risks with user-supplied paths; send_from_directory
was designed to control those risks.
Answered By - atupal
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