[FIXED] PyQt5 connect to Websocket - wait for signal from server

Issue

I am trying to connect to a scanner which offers a REST Api over an apiport. Before I can do that I have to connect to the Scanner using PyQt5 and sign a challange. I have a C++ code as example but I can not find the corresponding PyQt Classes/Methods.

Basically I am looking for a way to replace these lines from C++:

QWebSocket socket;
QString address = "127.0.0.1";
QString port = "1234";
connect(&socket,&QWebSocket::textMessageReceived,this,&Client::onTextMessageReceived);
socket.open(QUrl(QString("ws://%1:%2").arg(address).arg(port)));

My problem is this line:

connect(&socket,&QWebSocket::textMessageReceived,this,&Client::onTextMessageReceived);

Can someone help me on this one? All I have till now is this: (but it throws the Error: TypeError: native Qt signal is not callable)

class Client(QtCore.QObject):
    def __init__(self, parent):
        super().__init__(parent)

        self.client =  QtWebSockets.QWebSocket("",QtWebSockets.QWebSocketProtocol.Version13,None)
        #self.client.error.connect(self.error)
        print("Trigger")
        trigger = self.client.textMessageReceived()


        #self.client.open(QUrl("ws://"+UDP_IP+":"+str(notificationsport)))

    def ontextmsgreceived():
        print("Text MSG received")

    def close(self):
        self.client.close()




global client
app = QApplication(sys.argv)
client = Client(app)
app.exec_()

Thanks a lot for your Help!

Solution

In PyQt the connection syntax is the following:

C++:

connect(sender, &Class_sender::some_signal, receiver, &Class_receiver::some_slot);

python:

sender.some_signal.connect(receiver.some_slot)

so in your case:

self.client.textMessageReceived.connect(self.ontextmsgreceived)

Another problem is that your slot is a method of the class so the first parameter must be the self, in addition the textMessageReceived signal sends a text as a parameter, so the slot must have the same parameter:

def ontextmsgreceived(self, message):
    print("Text MSG received", message)

Answered By - eyllanesc