Issue
First, sorry for my poor english. Actually, i make a script who find data on amazon webpage. I need to scrape asin on amazon webpage, with python and selenium. I've made this code for to scrape asin:
firstResult = driver.find_element_by_css_selector('div[data-index="1"]>div')
asin = firstResult.get_attribute('data-asin')
But its not work, i have some errors on results:
selenium.common.exceptions.NoSuchElementException: Message: no such element: Unable to locate element: {"method":"css selector","selector":"div[data-index="1"]>div"}
(Session info: headless chrome=96.0.4664.45)
The part of source code who has asin number, on webpage (ASIN is highlighted):
Anyone know how to make for to scrape this ASIN in python with selenium please? Ty for help!
Solution
You could wait and look for the span which is located beside that tag.
wait=WebDriverWait(driver, 60)
driver.get('https://www.amazon.fr/PlayStation-%C3%89dition-Standard-DualSense-Couleur/dp/B08H93ZRK9')
elem=wait.until(EC.presence_of_element_located((By.XPATH," //span[@class='a-list-item' and contains (.,'ASIN')]//span[2]")))
print(elem.text)
Imports:
from selenium.webdriver.common.by import By
from selenium.webdriver.support.ui import WebDriverWait
from selenium.webdriver.support import expected_conditions as EC
Outputs:
B08H93ZRK9
Another thing is that url actually has the same value at the end. Which could be obtained which a simple string manipulation of the driver.current_url,
https://www.amazon.fr/PlayStation-%C3%89dition-Standard-DualSense-Couleur/dp/ B08H93ZRK9
Answered By - Arundeep Chohan
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