[FIXED] Selenium Firefox Webdriver - need help locating button and with code to click button

Issue

I'm using Selenium and need to click on a button called Income Statement at http://www.tradingview.com/screener. Could anyone help me to find the button name and let me know if the code where I'm trying to implement it is correct. Any help much appreciated. Thanks!!

url = 'http://www.tradingview.com/screener'
driver = webdriver.Firefox()
driver.get(url)

button_element = driver.find_element_by_xpath("//input[@name='Income Statement']")
button_element.click()

Solution

There are 2 problems here:

1. You have to add wait / delay before accessing that element.
   This should preferably be done by expected conditions explicit waits.
2. You are using a wrong locator.

This should work better:

from selenium.webdriver.common.by import By
from selenium.webdriver.support.ui import WebDriverWait
from selenium.webdriver.support import expected_conditions as EC

url = 'http://www.tradingview.com/screener'
driver = webdriver.Firefox()
wait = WebDriverWait(driver, 20)
driver.get(url)
wait.until(EC.visibility_of_element_located((By.XPATH, "//div[@data-set='income_statement']"))).click()

Answered By - Prophet