[FIXED] Why is the decoder in an autoencoder uses a sigmoid on the last layer?

Issue

I am looking at this working variational auto encoder.

The main class

class VAE(nn.Module):
    def __init__(self):
        super(VAE, self).__init__()

        self.fc1 = nn.Linear(784, 400)
        self.fc21 = nn.Linear(400, 20)
        self.fc22 = nn.Linear(400, 20)
        self.fc3 = nn.Linear(20, 400)
        self.fc4 = nn.Linear(400, 784)

    def encode(self, x):
        h1 = F.relu(self.fc1(x))
        return self.fc21(h1), self.fc22(h1)

    def reparametrize(self, mu, logvar):
        std = logvar.mul(0.5).exp_()
        if torch.cuda.is_available():
            eps = torch.cuda.FloatTensor(std.size()).normal_()
        else:
            eps = torch.FloatTensor(std.size()).normal_()
        eps = Variable(eps)
        return eps.mul(std).add_(mu)

    def decode(self, z):
        h3 = F.relu(self.fc3(z))
        return F.sigmoid(self.fc4(h3))

    def forward(self, x):
        mu, logvar = self.encode(x)
        z = self.reparametrize(mu, logvar)
        return self.decode(z), mu, logvar

has

    def decode(self, z):
        h3 = F.relu(self.fc3(z))
        return F.sigmoid(self.fc4(h3))

I can't explain to myself why the last layer should be passed through a sigmoid before returning.

Please explain.

---

EDIT: I just checked without the sigmoid. Results are still nice. Now I am not sure if it is needed or not.

Solution

As mentioned in the answer by Jim J, sigmoid forces the output to the range [0, 1]. In this case, it's not because we want to interpret the output as a probability, rather it's done to force the output to be interpreted as pixel intensity of a grey scale image.

If you remove the sigmoid, the NN will have to learn that all the outputs should be in the range [0, 1]. The sigmoid might help making the learning process more stable.

Answered By - Sandro H