[FIXED] Comparing two dimensional arrays to one another

Issue

I want to write a code where it outputs the similarities for the values of arrays a,b,c. I want the code to check if there are any similar values between the arrays. I will be comparing b and c to a. So [ 0, 1624580882] exist when comparing a and b and so on. Both the columns must be equivalent for the comparison to work.

import numpy as np 

a= np.array([[         0, 1624580882],
 [         1, 1624584458],
 [         0, 1624589467],
 [         1, 1624592213],
 [         0, 1624595336],
 [         1, 1624596349]])

b= np.array([[         1, 1624580882],
 [         1, 1624584460],
 [         1, 1624595336],
 [         1, 1624596349]])


c = np.array([[         0, 1624580882],
 [         1, 1624584458],
 [         0, 1624589495],
 [         1, 1624592238],
 [         0, 1624595336],
 [         1, 1624596349]])

Expected Output:

b comparison
Similarities= None

c comparison
Similarities= [         0, 1624580882],[         1, 1624584464], [         0, 1624595350],[         1, 1624596380] 

Solution

I'm not giving you the actual solution rather I can help you with a simple function. You can design the rest of your code according to that function.

def compare_arrays(arr_1, arr_2):
    result = []
    for row in arr_1:
        result.append(row in arr_2)
    return result

Edit:

For getting the index of the duplicate values.

 from numpy.lib import recfunctions as rfn
 ndtype = [('a', int)]
 a = np.ma.array([1, 1, 1, 2, 2, 3, 3],mask=[0, 0, 1, 0, 0, 0, 1]).view(ndtype)
 rfn.find_duplicates(a, ignoremask=True, return_index=True)

Answered By - Fatin Ishrak Rafi