Issue
I have over a dozen spiders in a scrapy project with variety of items being extracted from different sources, including others elements mostly i have to copy same regex code over and over again in each spider for example
item['element'] = re.findall('my_regex', response.text)
I use this regex to get same element which is defined in scrapy items, is there a way to avoid copying? where do i put this in project so that i don't have to copy this in each spider and only add those that are different.
my project structure is default
any help is appreciated thanks in advance
Solution
I can copy regex in multiple spiders instead of importing object from other .py files, i understand they have the use case but here i don't want to add anything to any of the spiders but still want the element in result
There are some good answers to this but don't really solve the problem so after searching for days i have come to this solution i hope its useful for others looking for similar answer.
#middlewares.py
import yourproject.items import youritem()
#find the function and add your element
def process_spider_output(self, response, result, spider):
item = YourItem()
item['element'] = re.findall('my_regex', response.text)
now uncomment middleware from
#settings.py
SPIDER_MIDDLEWARES = {
'yourproject.middlewares.YoursprojectMiddleware': 543,
}
For each spider you will get element in result data, i am still searching for better solution and i will update the answer because it slows the spider,
Answered By - Assad Ali
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