[FIXED] Get two numpy arrays from an * args parameter function exactly as they were supplied to that function

Issue

I a function described as follows (very simplified version):

def my_func(*args):
    c = other_func(args)
    return c

And other_func is defined as:

def other_func(a, b):
    c = a + b
    return c

I have also two numpy arrays:

a = [[1.] [2.]]
b = [[2.] [5.]]

I want to pass a and b to my_func and retrieve them exactly as I passed them: The result I want is :

c = my_func(a, b)

With :

c = [[3.] [7.]]

But when I call my_func like above, I get this error:

TypeError: other_func missing 1 required positional argument: 'b'

I think the problem is that my_func is not able to unpack the data. I looked at an almost similar topic (link below) but It doesn't help me enough to fix my problem. Also, I don't want to use a Loop, it will not be practical for my work.

Link : How to split list and pass them as separate parameter?

Can anyone help me solve this?

Thank you in advance.

Solution

Change the line

c = other_func(args)

to

c = other_func(*args)

Answered By - NGilbert