[FIXED] Python: if condition for an another function result?

Issue

Solved: Thanks for your helps. i'm working dictionary and hash codes in one page, and there was a block problem. i thought, my logic is wrong but i checked all page, and i fixed blocks. its works fine right now.

Here's my problem:

d = {}
d['a'] = 'alpha'
d['b'] = 'beta'

missing_key = 'x' in d
if missing_key == True:
  print ("The key, you are looking for was successfully found!")
else:
  print ("The key, you are looking for was not found!")


print ("Here are keys in database:")
for k, r in enumerate(d.keys(), start=1)
  print ("Key {}: {}".format(k, r))

that for condition works perfectly. but i cant run that if condition. Where am i doing wrong ? Thanks for your help.

Getting this error:

File "C:/Python/dictionary-hash.py", line 33

if missing_key == True:

IndentationError: unexpected indent

also i'm using "Python 3.6" and "Anaconda Spyder"

Solution

There's nothing wrong with the logic in your code. Since the error is an IndentationError, it must be because you're using inconsistent indentation on that if line. Make sure that the indentation on each line is consistent (using same number of spaces/tabs). Probably there is a space at the beginning of that line that is causing the error.

Answered By - Henry Woody