[FIXED] Get path of tags using attribute field in XSD

Issue

My current task is to get information from XSD file (type of field, name of field etc). I have XSD file looks like that:

<?xml version="1.0" encoding="UTF-8"?>
<!-- edited with XMLSpy v2018 rel. 2 sp1 (x64) (http://www.altova.com) by test (123321) -->
<xs:schema xmlns:xs="http://www.w3.org/2001/XMLSchema" elementFormDefault="qualified" attributeFormDefault="unqualified">
    <xs:complexType name="attribute">
        <xs:annotation>
            <xs:documentation>Атрибуты ОГХ</xs:documentation>
        </xs:annotation>
        <xs:sequence>
            <xs:element name="owner_id">
                <xs:annotation>
                    <xs:documentation>Данные о балансодержателе</xs:documentation>
                </xs:annotation>
                <xs:complexType>
                    <xs:sequence>
                        <xs:element name="legal_person" type="xs:integer">
                            <xs:annotation>
                                <xs:documentation>ID балансодержателя</xs:documentation>
                            </xs:annotation>
                        </xs:element>
                    </xs:sequence>
                </xs:complexType>
            </xs:element>
            <xs:element name="snow_clean_area" type="xs:double">
                <xs:annotation>
                    <xs:documentation>Площадь вывоза снега, кв. м</xs:documentation>
                </xs:annotation>
            </xs:element>
        </xs:sequence>
    </xs:complexType>
</xs:schema>

As we can see, there is some fields <xs:element> with other <xs:element> inside (nesting).

I need to get the names of all elements in that XSD. BUT if an element is inside another one, I need to write the name as "all_prev_names;cur_name". For XSD that I showed before, it will be:

"owner_id;legal_person"
"snow_clean_area"

For more nesting, the name must have all previous names.

I wrote that code:

        def recursive(xml, name=None):
            res = xml.find_all('xs:element')

            if res:
                for elem in res:
                    if name:
                        yield from recursive(elem, elem['name'] + ';' + name)
                    else:
                        yield from recursive(elem, elem['name'])
            else:
                if name:
                    yield (name)
                else:
                    yield (xml['name'])

But there is a problem with duplicate paths. The result of that function will be:

"owner_id;legal_person"
"legal_person"
"snow_clean_area"

I need to fix that code, or get another idea, how to solve that task.

Solution

I found a solution, that is suitable for me. I use ElementTree.iterparse, not BeautifulSoup. Than, after each element I save my fields, and at the end of tag, save it to my structure:

def getXsd(self, typeNumber: int) -> t.List[t.Dict[str, str]]:
    paths = []
    for elem in self.xsds:
        if elem[0] == typeNumber:
            events = ("start", "end")
            codes = []
            type_field = None
            for event, elem in ET.iterparse(BytesIO(elem[1].encode("UTF-8")), events=events):
                if event == 'start' and elem.tag == '{http://www.w3.org/2001/XMLSchema}element':
                    codes.append(elem.attrib['name'])
                    if 'type' in elem.attrib:
                        type_field = elem.attrib['type']
                elif event == 'start' and elem.tag == '{http://www.w3.org/2001/XMLSchema}documentation':
                    if codes and type_field:
                        paths.append({'code': "".join([str(item).capitalize() for item in codes[::-1]]),
                                     'type': type_field,
                                     'name': elem.text})
                        type_field = None

                elif event == 'end' and elem.tag == '{http://www.w3.org/2001/XMLSchema}element':
                    codes.pop()
    return paths

The result is:

[{'code': 'Legal_personOwner_id', 'type': 'xs:integer', 'name': 'ID балансодержателя'}, {'code': 'Legal_personCustomer_id', 'type': 'xs:integer', 'name': 'ID заказчика'}, {'code': 'Improvement_object_categoryImprovement_object_category_id', 'type': 'xs:integer', 'name': 'Код категории озеленения'}, {'code': 'Legal_personDepartment_id', 'type': 'xs:integer', 'name': 'ID ведомственного ОИВ'}, {'code': 'Snow_clean_area', 'type': 'xs:double', 'name': 'Площадь вывоза снега, кв. м'}, {'code': 'Reservoir_area', 'type': 'xs:double', 'name': 'Водоемы, кв. м'}]

Answered By - magicarm22