[FIXED] Scrapy - Scrape multiple URLs using results from the first URL

Issue

1. I use Scrapy to scrape data from the first URL.
2. The first URL returns a response contains a list of URLs.

So far is ok for me. My question is how can I further scrape this list of URLs? After searching, I know I can return a request in the parse but it seems only can process one URL.

This is my parse:

def parse(self, response):
    # Get the list of URLs, for example:
    list = ["http://a.com", "http://b.com", "http://c.com"]
    return scrapy.Request(list[0])
    # It works, but how can I continue b.com and c.com?

May I do something like that?

def parse(self, response):
    # Get the list of URLs, for example:
    list = ["http://a.com", "http://b.com", "http://c.com"]

    for link in list:
        scrapy.Request(link)
        # This is wrong, though I need something like this

Full version:

import scrapy

class MySpider(scrapy.Spider):
    name = "mySpider"
    allowed_domains = ["x.com"]
    start_urls = ["http://x.com"]

    def parse(self, response):
        # Get the list of URLs, for example:
        list = ["http://a.com", "http://b.com", "http://c.com"]

        for link in list:
            scrapy.Request(link)
            # This is wrong, though I need something like this

Solution

I think what you're looking for is the yield statement:

def parse(self, response):
    # Get the list of URLs, for example:
    list = ["http://a.com", "http://b.com", "http://c.com"]

    for link in list:
        request = scrapy.Request(link)
        yield request

Answered By - Frank Martin