[FIXED] Checking if a number is the sum of 2 other numbers

Issue

Problem Statement

Given a list of numbers and a number k, return whether any two numbers from the list add up to k.

Example

Given [1, 2, 3] and k = 5, return True since 2 + 3 = 5.

This is what I've tried to do:

def pairs(n):
    for i in range(len(n)):
        for j in range(i+1, len()):
            yield n[i], n[j]


def ListCheck():
    number = input("Give me a number:")
    val = int(number)
    nums = [1,2,3]
    for i, j in pairs(nums):
        if j + i == val:
            print(True)
            break


ListCheck()

I'm getting an error when I run it, and I can't understand why.

Solution

def issumoftwo(lst,num):
    for x in lst:
        for y in lst:
            if x+y==num and lst.index(x)!=lst.index(y):
                return True
    return False
lst=[1,2,3]
num=int(input("Give me a Number: "))
print(issumoftwo(lst,num))

Output

Give me a number: 5
True

Answered By - Bitto Bennichan