[FIXED] How do I repeat binary pattern and ratio in matrix effectively in python?

Issue

I want to efficiently print a matrix in python that follows a specific pattern in the columns of 5 0s then 3 1s then 5 0s and so on and so forth as shown below for 1000 rows:

0000
0000
0000
0000
0000
1111
1111
1111
0000
0000
0000
0000
0000
1111
1111
1111
...

Solution

You can use a combination of np.block and list comprehension:

out = np.block([[np.zeros((5, 4))],[np.ones((3, 4))]] * 125).astype(int)

This can be functionalized to answer similar questions like so:

def block_repeat(size, *args):
    block = np.block([[a] for a in args])
    return np.resize(block, (size,) + block.shape[1:])

block_repeat(1000, np.zeros((5,4)), np.ones((3,4)))
Out[]: 
array([[0., 0., 0., 0.],
       [0., 0., 0., 0.],
       [0., 0., 0., 0.],
       ...,
       [1., 1., 1., 1.],
       [1., 1., 1., 1.],
       [1., 1., 1., 1.]])

Answered By - Daniel F