Issue
I have the following code:
import asyncio
async def myfunc(i):
print("hello", i)
await asyncio.sleep(i)
print("world", i)
async def main():
asyncio.create_task(myfunc(2))
asyncio.create_task(myfunc(1))
asyncio.run(main())
It outputs:
hello 2
hello 1
Notice that world
isn't printed anywhere. Why is the output we see being produced? I was expecting:
hello 2
hello 1
world 1
world 2
Because I thought that the asyncio.sleep(i)
calls would yield execution to the event loop, at which point the event loop would reschedule them after their respective wait times. Clearly I am misunderstanding. Can someone explain?
Solution
Found a much simpler solution than the one provided by @eyllanesc here. Turns out there is a function that implements it
Answered By - Code M4aster
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