[FIXED] Regex: Match between delimiters (a letter and a special character) in a string to form new sub-strings

Issue

I was working on a certain problem where I have form new sub-strings from a main string.

For e.g. in_string=ste5ts01,s02,s03

The expected output strings are ste5ts01, ste5ts02, ste5ts03

There could be comma(,) or forward-slash (/) as the separator and in this case the delimiters are the letter s and ,

The pattern I have created so far:

pattern = r"([^\s,/]+)(?<num>\d+)([,/])(?<num>\d+)(?:\2(?<num>\d+))*(?!\S)"

The issue is, I am not able to figure out how to give the letter 's' as one of the delimiters.

Any help will be much appreciated!

Solution

You might use an approach using the PyPi regex module and named capture groups which are available in the captures:

=(?<prefix>s\w+)(?<num>s\d+)(?:,(?<num>s\d+))+

Explanation

• = Match literally
• (?<prefix>s\w+) Match s and 1+ word chars in group prefix
• (?<num>s\d+) Capture group num match s and 1+ digits
• (?:,(?<num>s\d+))+ Repeat 1+ times matching , and capture s followed by 1+ digits in group num

Example

import regex as re

pattern = r"=(?<prefix>s\w+)(?<num>s\d+)(?:,(?<num>s\d+))+"
s="in_string=ste5ts01,s02,s03"

matches = re.finditer(pattern, s)
for _, m in enumerate(matches, start=1):
    print(','.join([m.group("prefix") + c for c in m.captures("num")]))

Output

ste5ts01,ste5ts02,ste5ts03

Answered By - The fourth bird