Issue
I am passing a list from flask function to another function, and getting this value error.
My code at sending end:
@app.route('/process', methods=['POST'])
def process():
name = request.form['name']
comment = request.form['comment']
wickets = request.form['wickets']
ga = request.form['ga']
ppballs = request.form['ppballs']
overs = request.form['overs']
score = [name,comment,wickets,ga,ppballs,overs]
results = []
results = eval_score(score)
print results
Receiver end :
def ml_model(data):
col = pd.DataFrame(data,columns=['runs','balls', 'wickets', 'ground_average', 'pp_balls_left', 'total_overs'])
predicted = predictor(col)
Trace of Error:
...
line 1598, in dispatch_request
return self.view_functions[rule.endpoint](**req.view_args)
File "/Users/sbk/guestbook/guestbook.py", line 26, in process
results = eval_score(score)
File "/Users/sbk/guestbook/eval_score.py", line 6, in eval_score
col = pd.DataFrame(data,columns=['runs','balls', 'wickets', 'ground_average', 'pp_balls_left', 'total_overs'])
File "/Users/sbk/anaconda2/lib/python2.7/site- packages/pandas/core/frame.py", line 385, in __init__
copy=copy)
File "/Users/sbk/anaconda2/lib/python2.7/site-packages/pandas/core/frame.py", line 533, in _init_ndarray
return create_block_manager_from_blocks([values], [columns, index])
File "/Users/sbk/anaconda2/lib/python2.7/site-packages/pandas/core/internals.py", line 4631, in create_block_manager_from_blocks
construction_error(tot_items, blocks[0].shape[1:], axes, e)
File "/Users/sbk/anaconda2/lib/python2.7/site-packages/pandas/core/internals.py", line 4608, in construction_error
Open an interactive python shell in this framepassed, implied))
Please let me know where I am going wrong.
Solution
Simply change
col = pd.DataFrame(data, columns=['runs','balls', 'wickets', 'ground_average', 'pp_balls_left', 'total_overs'])
for
col = pd.DataFrame([data], columns=['runs','balls', 'wickets', 'ground_average', 'pp_balls_left', 'total_overs'])
You want [data]
for pandas
to understand they're rows.
Simple illustration:
a = [1, 2, 3]
>>> pd.DataFrame(a)
0
0 1
1 2
2 3
>>> pd.DataFrame([a])
0 1 2
0 1 2 3
Answered By - rafaelc
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