[FIXED] How to convert numpy datetime64 into datetime

Issue

I basically face the same problem posted here:Converting between datetime, Timestamp and datetime64

but I couldn't find satisfying answer from it, my question how to extract datetime from numpy.datetime64 type:

if I try:

np.datetime64('2012-06-18T02:00:05.453000000-0400').astype(datetime.datetime)

it gave me: 1339999205453000000L

my current solution is convert datetime64 into a string and then turn to datetime again. but it seems quite a silly method.

Solution

Borrowing from Converting between datetime, Timestamp and datetime64

In [220]: x
Out[220]: numpy.datetime64('2012-06-17T23:00:05.453000000-0700')

In [221]: datetime.datetime.utcfromtimestamp(x.tolist()/1e9)
Out[221]: datetime.datetime(2012, 6, 18, 6, 0, 5, 452999)

Accounting for timezones I think that's right. Looks rather clunky though.

Using int() is more explicit (I think) than tolist()):

In [294]: datetime.datetime.utcfromtimestamp(int(x)/1e9)
Out[294]: datetime.datetime(2012, 6, 18, 6, 0, 5, 452999)

or to get datetime in local:

In [295]: datetime.datetime.fromtimestamp(x.astype('O')/1e9)

But in the test_datetime.py file https://github.com/numpy/numpy/blob/master/numpy/core/tests/test_datetime.py

I find some other options - first convert the general datetime64 to one of the format that specifies units:

In [296]: x.astype('M8[D]').astype('O')
Out[296]: datetime.date(2012, 6, 18)

In [297]: x.astype('M8[ms]').astype('O')
Out[297]: datetime.datetime(2012, 6, 18, 6, 0, 5, 453000)

This works for arrays:

In [303]: np.array([[x,x],[x,x]],dtype='M8[ms]').astype('O')[0,1]
Out[303]: datetime.datetime(2012, 6, 18, 6, 0, 5, 453000)

Answered By - hpaulj