Issue
Here is my code:
import pandas as pd
from sqlalchemy import create_engine
db_username = "my_username"
db_pw = "my_password"
db_to_use = "my_database"
#####
engine = create_engine(
"postgresql://" +
db_username + ":" +
db_pw +
"@localhost:5432/" +
db_to_use
)
#####
connection = engine.connect()
fac_id_list = connection.execute (
"""
select distinct
a.name,
replace(regexp_replace(regexp_replace(a.logo_url,'.*/logo','','i'),'production.*','','i'),'/','') as new_logo
from
sync_locations as a
inner join
public.vw_locations as b
on
a.name = b.location_name
order by
new_logo
"""
)
I want to put the results of fac_id_list
into two separate lists. One list will contain all of the values from a.name
and the other new_logo
.
How can I do this?
sql_results = []
for row in fac_id_list:
sql_results.append(row)
This puts every column in my SQL query into a list, but I want them separated.
Solution
When you loop over the results, you can spread them into separate variables and append them to the corresponding lists
names = []
logos = []
for name, logo in fac_id_list:
names.append(name)
logos.append(log)
Answered By - Barmar
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