Issue
How do I count the number of 0
s and 1
s in the following array?
y = np.array([0, 0, 0, 1, 0, 1, 1, 0, 0, 0, 0, 1])
y.count(0)
gives:
numpy.ndarray
object has no attributecount
Solution
a = numpy.array([0, 3, 0, 1, 0, 1, 2, 1, 0, 0, 0, 0, 1, 3, 4])
unique, counts = numpy.unique(a, return_counts=True)
dict(zip(unique, counts))
# {0: 7, 1: 4, 2: 1, 3: 2, 4: 1}
Non-numpy way:
Use collections.Counter
;
import collections, numpy
a = numpy.array([0, 3, 0, 1, 0, 1, 2, 1, 0, 0, 0, 0, 1, 3, 4])
collections.Counter(a)
# Counter({0: 7, 1: 4, 3: 2, 2: 1, 4: 1})
Answered By - Ozgur Vatansever
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