Issue
I am new to python. In Python, I want to compare two lists of dictionaries
Below are 2 list of dictionary I want to compare based on key which is "zrepcode" and id which is the number "1", "3", and "4"...
Code snippet is as follows:
List1 = [{"3":[{"period":"P13","value":10,"year":2022}],"zrepcode":"55"},{"1":[{"period":"P10","value":5,"year":2023}],"zrepcode":"55"}]
List2 = [{"1":[{"period":"P1","value":10,"year":2023},{"period":"P2","value":5,"year":2023}],"zrepcode":"55"},{"3":[{"period":"P1","value":4,"year":2023},{"period":"P2","value":7,"year":2023}],"zrepcode":"55"},{"4":[{"period":"P1","value":10,"year":2023}],"zrepcode":"55"}]
After Comparision, we need the unique list of dictionary from list2.
res = [{"4":[{"period":"P1","value":10,"year":2023}],"zrepcode":"55"}]
This is the expected output, Now I don't know how I get this.
Solution
You can use list comprehension to filter a list.
[x for x in list if condition]
and any() to see if a list has any elements matching a condition
any(condition for y in list)
or in your case, since you want those that don't exist in the other
[x for x in list2 if not any(your_condition for y in list1)]
To check if two elements have the same zrepcode value you can just compare them like
x['zrepcode'] == y['zrepcode']
Since your other point of comparison is a key and there are only two keys in each, you can compare the keys of both
x.keys() == y.keys()
Combine everything
[x for x in list2 if not any(x['zrepcode'] == y['zrepcode'] and x.keys() == y.keys() for y in list1)]
Answered By - JollyJoker
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