[FIXED] How to find if the elements in a list are in ascending order or in descending order without using sort function?

Issue

The question which was given to me in python is , Accept a list with n number of terms and check if whether the elements are in ascending order , descending order or not in order without using sort function and def too.

Please Help me in doing this program.

Code:

a=list(input("Enter elements:"))
for i in range(len(a)):
    for j in range(i):
        if a[j]<=a[j+1]:
            print("It is in ascending order")
        elif a[j]>=a[j+1]:
            print("It is in descending order")
        else:
            print("It is not in order")

Solution

def which_order(list1):
    isAscending = True
    isDescending = True
    for i in range(1,len(list1)):
        if(list1[i] >= list1[i-1]):
            isDescending = False
        elif(list1[i] <= list1[i-1]):
            isAscending = False
        if((not isAscending) and (not isDescending)):
            print("The list is not sorted in either order.")
            break
    if(isAscending):
        print("The list is sorted in ascending order.")
    if(isDescending):
        print("The list is sorted in descending order.")

Sample output:

list1 = [1,2,3,4]
list2 = [9,8,7,6]
list3 = [1,9,8,7,6]
which_order(list1)
which_order(list2)
which_order(list3)

The list is sorted in ascending order.
The list is sorted in descending order.
The list is not sorted in either order.

Answered By - Satheesh K