Issue
This is the graph that I got in the list
My question is how to get each minimum and maximum of each period in the list? Following the graph I want to get the 1st maximum at point 1
, 1st minimum at point 30
, 2nd maximum at point 62
, 2nd minimum at point 94
I have tried but it got the wrong point since the value in the list is not stable as you can see on the graph
This is my code that I have tried
max_1 = 0
max_1_pos = 0
min_1_pos = 0
max_2 = 0
max_2_pos = 0
min_2_pos = 0
img_list_pix =[218, 225, 224, 224, 224, 220, 217, 215, 216, 216,
216, 215, 214, 215, 214, 214, 213, 210, 210, 205,
207, 204, 205, 201, 200, 201, 201, 197, 202, 203,
196, 196, 196, 196, 198, 198, 199, 202, 202, 205,
205, 205, 207, 206, 208, 207, 209, 214, 212, 213,
215, 218, 220, 219, 218, 220, 223, 222, 224, 224,
224, 222, 225, 222, 222, 222, 222, 223, 223, 221,
223, 222, 223, 219, 218, 216, 215, 214, 212, 212,
211, 211, 207, 206, 205, 204, 202, 199, 199, 198,
197, 195, 193, 191, 191, 193, 191, 196]
for i in range(len(img_list_pix)):
if img_list_pix[i] >= max_1:
max_1 = img_list_pix[i]
max_1_pos = i
else:
break
min_1 = max_1
print(f"max_1:{max_1} | i:{i}")
for i in range(max_1_pos + 1, len(img_list_pix)):
if img_list_pix[i] <= min_1:
min_1 = img_list_pix[i]
min_1_pos = i
else:
break
max_2 = min_1
print(f"min_1:{min_1} | i:{i}")
for i in range(min_1_pos + 1, len(img_list_pix)):
if img_list_pix[i] >= max_2:
max_2 = img_list_pix[i]
max_2_pos = i
else:
break
min_2 = max_2
print(f"max_2:{max_2} | i:{i}")
for i in range(max_2_pos + 1, len(img_list_pix)):
if img_list_pix[i] <= min_2:
min_2 = img_list_pix[i]
min_2_pos = i
else:
break
print(f"min_2:{min_2} | i:{i}")
The results of the aforementioned code is:
max_1:225 | i:2
min_1:215 | i:8
max_2:216 | i:11
min_2:214 | i:13
Thanks in Advance.
Solution
Your modified code will be as:
F1 = 0
F1_lim = 15
for i in range(len(img_list_pix)):
if img_list_pix[i] > max_1:
max_1 = img_list_pix[i]
max_1_pos = i
F1 = 0
elif F1 <= F1_lim:
F1 += 1
if img_list_pix[i] > max_1:
max_1 = img_list_pix[i]
max_1_pos = i
F1 = 0
else:
F1 = 0
break
print(f"max_1:{max_1} | i:{max_1_pos}")
min_1 = max_1
for i in range(max_1_pos + 1, len(img_list_pix)):
if img_list_pix[i] < min_1:
min_1 = img_list_pix[i]
min_1_pos = i
F1 = 0
elif F1 <= F1_lim:
F1 += 1
continue
else:
F1 = 0
break
print(f"min_1:{min_1} | i:{min_1_pos}")
max_2 = min_1
for i in range(min_1_pos + 1, len(img_list_pix)):
if img_list_pix[i] > max_2:
max_2 = img_list_pix[i]
max_2_pos = i
F1 = 0
elif F1 <= F1_lim:
F1 += 1
if img_list_pix[i] > max_2:
max_2 = img_list_pix[i]
max_2_pos = i
F1 = 0
else:
F1 = 0
break
print(f"max_2:{max_2} | i:{max_2_pos}")
min_2 = max_2
for i in range(max_2_pos + 1, len(img_list_pix)):
if img_list_pix[i] < min_2:
min_2 = img_list_pix[i]
min_2_pos = i
F1 = 0
elif F1 <= F1_lim:
F1 += 1
continue
else:
F1 = 0
break
print(f"min_2:{min_2} | i:{min_2_pos}")
F1_lim
is number of indices after index of the founded value to compare with, and can be changed by the user. This code will gives the following results:
max_1:225 | i:1
min_1:196 | i:30
max_2:225 | i:62
min_2:191 | i:93
The code will gives the first occurrence of the minimum or maximum values for valleys or peaks, e.g. for min_2
it will return 93. For getting the last one with the same magnitude as 93 i.e. 96 for min_2
in the specified range F1_lim = 15
, less than and greater than operators must be substituted by less than equal and greater than equal operators.
Answered By - Ali_Sh
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