Issue
I am querying a single value from my data frame which seems to be 'dtype: object'. I simply want to print the value as it is with out printing the index or other information as well. How do I do this?
col_names = ['Host', 'Port']
df = pd.DataFrame(columns=col_names)
df.loc[len(df)] = ['a', 'b']
t = df[df['Host'] == 'a']['Port']
print(t)
EXPECTED OUTPUT: b
Solution
If you can guarantee only one result is returned, use loc
and call item
:
>>> df.loc[df['Host'] == 'a', 'Port'].item()
'b'
Or, similarly,
>>> df.loc[df['Host'] == 'a', 'Port'].values[0]
'b'
...to get the first value (similarly, .values[1]
for the second). Which is better than df.loc[df['Host'] == 'a', 'Port'][0]
because, if your DataFrame looks like this,
Host Port
1 a b
Then "KeyError: 0" will be thrown—
df.loc[df['Host'] == 'a', 'Port'][0]
---------------------------------------------------------------------------
KeyError Traceback (most recent call last)
Alternatively, use at
:
>>> df.at[df['Host'].eq('a').idxmax(), 'Port']
'b'
The drawback is that if 'a' doesn't exist, idxmax
will return the first index (and return an incorrect result).
Answered By - cs95
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