[FIXED] Pass a path-variable to a subprocess in Python

Issue

im new to subprocessing and I have a question. I can't find a proper solution online.

I want my path to be in a variable --> that will be passed to a function --> that will be passed to a subprocess.
I'm not allowed to show my real code, but this simple example (that I just can't get to work) would help me a lot.
This code snippet should do:

1. Just take my path from a variable.
2. "cd" the path in CMD.
3. Open a file that is located in this path.

So far I tried:

import subprocess 

test_path = "C:/randome_path/.."

def Test_Function(test_path):         
    subprocess.call("cd", test_path, shell = True)                                                                                                                                                          
    subprocess.call("python file.py", shell = True)
    
Test_Function() 

My ErrorMessage is:
TypeError: Test_Function() missing 1 required positional argument: 'test_path'

Thank you for your time!

Solution

First you need to pass a parameter to your function because that's how you declarerd:

Test_Function(test_path) # here the function call with parameter 

or using the key-value "approach"

another_path = # ...
Test_Function(test_path=another_path)

Second: the command is expecting a string not a further parameter

subprocess.call(f"python file.py", shell=True, cwd=test_path) 

---

Note 1 to execute such command python file.py it is assumed that python's path is declared in some environment variable

Note 2 that subprocess may have some different "behaviour" under Windows

Try without shell=True. Now the commands should be given as a list of strings

def Test_Function(test_path):         
    subprocess.call(["python", "file.py"], cwd=test_path)

Answered By - cards