[FIXED] python: append() into zip() problem. 'zip' object has no attribute 'append'

Issue

Hope your days are going well :)

I am learning python recently with code academy site, and they gave me an example about zip() and append().

last_semester_gradebook = [("politics", 80), ("latin", 96), ("dance", 97), ("architecture", 65)]
subjects = ["physics", "calculus", "poetry", "history"]
grades = [98, 97, 85, 88]
subjects.append("computer science")
grades.append(100)
gradebook = zip(subjects, grades)

#This code is the problem
gradebook.append(("visual arts", 93))

print(list(gradebook))

This is the code I made but it gives me an error.

Traceback (most recent call last):
  File "script.py", line 9, in <module>
    gradebook.append(("visual arts", 93))
AttributeError: 'zip' object has no attribute 'append'

I would search for the error first for normal case, but the problem is, the code I wrote is exactly same as the code they gave me as an solution. That is why I am confused and asking here. Is it the error of the site or the solution is wrong?

Thank you for your attention

Solution

The problem is that zip is an iterator, not a sequence. I suspect that you have some old or untested code, not compatible with the current Python version. You zip result is usable as the target of a for statement, but has no append attribute -- it's a special type of function.

The conversion is easy enough: make a list from it earlier:

gradebook = list(zip(subjects, grades))

#This code is the problem
gradebook.append(("visual arts", 93))

print(gradebook)

Answered By - Prune