Issue
How do I reorganize elements of A (shape = (1,7,2))
to generate new array A1 (shape = (1,7,2))
in order of increasing j
? In A[0,0]= array([0, 1])
, j
refers to 1
in [0,1]
.
It would be great to have something very generic so that the code can deal with when shape of A
becomes very large, say (1,1000,2)
.
import numpy as np
A = np.array([[[0, 1],[0, 2],[1, 3],[2, 5],[3, 4],[4, 7],[5, 6]]])
print("A =", A.shape)
The desired output is
A1 = np.array([[[0, 1],[0, 2],[1, 3],[3, 4],[2, 5],[5, 6],[4, 7]]])
Solution
The order is defined first, then the array is sorted by order.
A = np.array([[[0, 1],[0, 2],[1, 3],[2, 5],[3, 4],[4, 7],[5, 6]]])
order = A[0,:, 1].argsort()
A =np.array([A[0][order]])
print(A)
Answered By - Masoud Gheisari
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