[FIXED] skipping a certain range of a list at time in python

Issue

I have a array, I want to pick first 2 or range, skip the next 2, pick the next 2 and continue this until the end of the list

list = [2, 4, 6, 7, 9,10, 13, 11, 12,2]
results_wanted = [2,4,9,10,12,2] # note how it skipping 2. 2 is used here as and example

Is there way to achieve this in python?

Solution

Taking n number of elements and skipping the next n.

l = [2, 4, 6, 7, 9, 10, 13, 11, 12, 2]
n = 2
wanted = [x for i in range(0, len(l), n + n) for x in l[i: i + n]]
### Output : [2, 4, 9, 10, 12, 2]

Answered By - Vikrant Sharma