Issue
I'm testing some code with *args
and **kwargs
, and I wrote a dictionary for the **kwargs
. For some reason, I'm getting
def func(*args, **kwargs):
if args:
second_test(*args)
elif kwargs:
second_test(**kwargs)
def second_test(stringa, integera, floata):
print("Name: %s, Problems Correct: %d, Points: %f" % (stringa, integera, floata))
profile_1 = ["David", 21, 132.00]
func(*profile_1)
profile_1a = {'Name': 'David', 'Problems Correct': 21, 'Points': 132.00}
func(**profile_1a)
The code starts from line 44
and ends at line 57
. This is the error I'm getting:
TypeError: second_test() got an unexpected keyword argument 'Name'
I've googled "unexpected keyword argument", but I can never find a definition; only other stackoverflow articles. What is wrong with my code?
Solution
When passing kwargs
into a function, it expects to find the exact variable name in the list. If instead your dictionary keys were stringa
, integera
, and floata
the function would work without problem.
So you either need to change your function variable names or change the key names in your dictionary to get this to work
Answered By - Novice
0 comments:
Post a Comment
Note: Only a member of this blog may post a comment.