Issue
I am new to djangorest and am not sure how to even go about this.
I have a Rest API that takes a post-request (with a list of parameters) and returns a list of items from a model via a serializer. It all works great.
I need to add a "rank" or rather a "relevancy score" to the items in my returned list. I can calculate the rank fine - I am doing it in the REST view - what I don't understand is how to pass the rank back with the serialized model class in the response.
I could create an entirely new object and pass it with the item ids.... but what I would rather do is attach a transient field: {"rank": value }
to each item in my list.
Can I do this?
Edit: Was asked for code. Here is what I am trying to do. The serializer class is just a basic all fields serializer.
@api_view(['GET', 'POST'])
def getServices(request):
...
items = getItems(request.data) #returns relevent items
for item in items:
rank = calculateRank(item,request.data) #caculates rank based on a ranking model
###
# I would like add the rank to the item here... unless there is another way?
###
...
serializer = ItemSerializer(items, many=True)
return Response(serializer.data, status=status.HTTP_200_OK)
Edit: Additional requirement. I dont always want the rank. The serializer should be able to handle the item with or without a rank field. Or would that require two serializers?
Solution
First you can add the rank field into the item.
@api_view(['GET', 'POST'])
def getServices(request):
...
items = getItems(request.data) #returns relevent items
for item in items:
item["rank"] = calculateRank(item, request.data)
...
serializer = ItemSerializer(items, many=True)
return Response(serializer.data, status=status.HTTP_200_OK)
And you can add the rank field in the serializer too.
class ItemSerializer(serializers.ModelSerializer):
...
rank = serializers.IntegerField(read_only = True, required = False)
...
Answered By - Metalgear
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