Issue
I have an array in the following form where the first two columns are supposed to be indices of a 2-dimensional array and the following columns are arbitrary values.
data = np.array([[ 0. , 1. , 48. , 4. ],
[ 1. , 2. , 44. , 4.4],
[ 1. , 1. , 34. , 2.3],
[ 0. , 2. , 55. , 2.2],
[ 0. , 0. , 42. , 2. ],
[ 1. , 0. , 22. , 1. ]])
How do I combine the indices data[:,:2]
with their values data[:,2:]
such that the resulting array is accessible by the indices in the first two columns.
In my example that would be:
result = np.array([[[42. , 2. ], [48. , 4. ], [55. , 2.2]],
[[22. , 1. ], [34. , 2.3], [44. , 4.4]]])
I know that there is a trivial solution using python loops. But performance is a concern since I'm dealing with a huge amount of data. Specifically it's output of another program that I need to process.
Maybe there is a relatively trivial numpy solution as well. But I'm kind of stuck.
If it helps the following can be safely assumed:
- All numbers in the first two columns are whole numbers (although the array consists of floats).
- Every possible index (or rather combinations of indices) in the original array is used exactly once. I.e. there is guaranteed to be exactly one entry of the form
[i, j, ...]
. - The indices start at 0 and I know the highest indices beforehand.
Edit:
Hmm. I see now how my example is misleading. The truth is that some of my input arrays are sorted, but that's unreliable. So I shouldn't assume anything about the order. I reordered some rows in my example to make it clearer. In case anyone wants to make sense of the answer and comment below: In my original question the array appeared to be sorted by the first two columns.
Solution
find row
, column
, depth
base your data array, then fill like below:
import numpy as np
data = np.array([[ 0. , 0. , 42. , 2. ],
[ 0. , 1. , 48. , 4. ],
[ 0. , 2. , 55. , 2.2],
[ 1. , 0. , 22. , 1. ],
[ 1. , 1. , 34. , 2.3],
[ 1. , 2. , 44. , 4.4]])
row = int(max(data[:,0]))+1
col = int(max(data[:,1]))+1
depth = len(data[0, 2:])
out = np.zeros([row, col, depth])
out = data[:, 2:].reshape(row,col,depth)
print(out)
Output:
[[[42. 2. ]
[48. 4. ]
[55. 2.2]]
[[22. 1. ]
[34. 2.3]
[44. 4.4]]]
Answered By - I'mahdi
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