Issue
I need to detect which spheres are connected to each other. If we have:
radii = np.array([2, 1, 1, 2, 2, 0.5])
poss = np.array([[7, 7, 7], [7.5, 8.5, 6], [0, 0, 0], [-1, -2, -1], [1, 1, 1], [2, 1, 3]])
I want a Boolean array (shape = (number of groups, number of spheres)
) or array/lists of arrays/lists of indices that shows which of the spheres are connected. So, the expected results for this example must be something like:
Boolean_array = np.array([[1, 1, 0, 0, 0, 0], [0, 0, 1, 1, 1, 1]], dtype=bool)
object_array = np.array([[0, 1], [2, 3, 4, 5]])
I tried to find a solution with networkx
(I'm not very familiar with it) and IDK if this library can help where we have spheres with different radii. I guess, returned ends_ind in my previous code can be helpful in this regard and I tried to use that as:
G = nx.Graph([*ends_ind])
L = [nx.node_connected_component(G, 0)]
for i in range(len(radii)):
iter = 0
for j in L:
if i in j:
iter += 1
if iter == 0:
L.append(nx.node_connected_component(G, i))
Which will not work. The error:
Traceback (most recent call last):
File "C:/Users/Ali/Desktop/check_2.py", line 31, in <module>
L.append(nx.node_connected_component(G, i))
File "<class 'networkx.utils.decorators.argmap'> compilation 8", line 4, in argmap_node_connected_component_5
File "C:\Users\Ali\anaconda3\envs\PFC_FiPy\lib\site-packages\networkx\algorithms\components\connected.py", line 185, in node_connected_component
return _plain_bfs(G, n)
File "C:\Users\Ali\anaconda3\envs\PFC_FiPy\lib\site-packages\networkx\algorithms\components\connected.py", line 199, in _plain_bfs
nextlevel.update(G_adj[v])
File "C:\Users\Ali\anaconda3\envs\PFC_FiPy\lib\site-packages\networkx\classes\coreviews.py", line 82, in __getitem__
return AtlasView(self._atlas[name])
KeyError: 11
Since using my previous code with other libraries will be an inefficient code (if it can solve the issue), I am seeking for any libraries, e.g. networkx
, or methods that can do it in a more efficient way, if possible.
What is the best way to get my expected results, particularly for large number of spheres (~100000).
Solution
You're trying to utilize networkx too early, here. First, you should calculate the geometrical distances for each pair of spheres. A useful trick for this is:
xyz_distances = poss.reshape(6, 1, 3) - poss.reshape(1, 6, 3)
distances = np.linalg.norm(xyz_distances, axis=2)
This gets you a symmetric 6x6 array of Euclidean distances between the sphere centers. Now, we need to compare the maximum possible distances. This is just the sum of radii for each pair of spheres, once again a 6x6 array, which we can calculate as
maximum_distances = radii.reshape(6, 1) + radii.reshape(1, 6)
And now we can compare the two:
>>> connections = distances < maximum_distances
>>> connections
array([[ True, True, False, False, False, False],
[ True, True, False, False, False, False],
[False, False, True, True, True, False],
[False, False, True, True, False, False],
[False, False, True, False, True, True],
[False, False, False, False, True, True]])
Which translates to two groups, just like you wanted - and you can get your second expected array via
>>> G = nx.Graph(connections)
>>> list(nx.connected_components(G))
[{0, 1}, {2, 3, 4, 5}]
Note that this whole thing is going to scale as N^2 in the number of spheres, and you might need to optimize that somehow (say, via scipy.spatial.ckdtree
).
Answered By - Dominik StaĆczak
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