Issue
I'm trying to get a similar script. VIDEO
No clue how he did this, working in every browser.
I'm not sure how to grab and check the url filename.
1 - open a text file containing a list with URLs (example.com/file.exe, anotherurl.com/file2.exe)
2 - for every url, open a browser tab, download the file and check if file exists
3 - Print "file downloaded" else "download failed" or calculate the fail ratio
My code, it worked for a single url when I know the filename. I've been trying to make it work for url lists. It should grab the filename in the url path /file.exe
from selenium import webdriver
from selenium.webdriver.chrome.options import Options
import time
import os.path
import requests
op = webdriver.ChromeOptions()
p = {'download.default_directory': 'C:\\Users\\VM\\Downloads'}
op.add_experimental_option('prefs', p)
driver = webdriver.Chrome(executable_path="C:\\chromedriver.exe",
options=op)
with open("C:\\Users\\VM\\Downloads\\urls.txt",'r') as file:
for url in file.readlines():
driver.get(url);
time.sleep(5)
if os.path.isfile('CHECK URL PATH FILENAME'):
print("File download is completed")
else:
print("File download is not completed")
Solution
What you can do is every time before you download file clean a folder(Delete all files) and then after hitting url check if atleast one file is present if file is present you can check file name contains '.exe'
// clean folder by deleting all files from download location folder
driver.get(url);
time.sleep(5)
if os.path.isfile('CHECK URL PATH FILENAME'): // get list of files present in folder ane verify if file name ends with .exe
print("File download is completed") // Write code to delete all files after this line.
else:
print("File download is not
Answered By - Ketan Pardeshi
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