[FIXED] Finding how many times a certain character appears in a multiplied string

Issue

We want to find the number of 'a's in a given string s multiplied infinite times. We will be given a number n that is the slicing size of the infinite string.

sample input:
aba 10

output:
7

Here aba is multiplied with 10, resulting in 'abaabaabaa' and the no. of 'a's are 7. This is my code:

def repeatedString(s, n):
    count = 0
    inters = s * n
    reals = s[0:n+1]
    for i in reals:
        if (i == 'a'):
            count += 1
    return count

I'm getting 2 instead of 7 as the output (test case 'aba' 10). Where did I go wrong? I just multiplied the given string with n because it will never be greater than the slicing size.

Here's the link to the problem: https://www.hackerrank.com/challenges/repeated-string/problem

Solution

There's no reason to slice the string

def repeatedString(s, n):
    count = 0
    for index, i in enumerate(s*n):
        if index >= n:
            return count
        if(i == 'a'):
            count += 1
    # empty string
    return count

Answered By - A. Abramov